1x^2+14x+5=0

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Solution for 1x^2+14x+5=0 equation: 


Simplifying
1x2 + 14x + 5 = 0

Reorder the terms:
5 + 14x + 1x2 = 0

Solving
5 + 14x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + 14x + -5 + x2 = 0 + -5

Reorder the terms:
5 + -5 + 14x + x2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 14x + x2 = 0 + -5
14x + x2 = 0 + -5

Combine like terms: 0 + -5 = -5
14x + x2 = -5

The x term is 14x.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14x + 49 + x2 = -5 + 49

Reorder the terms:
49 + 14x + x2 = -5 + 49

Combine like terms: -5 + 49 = 44
49 + 14x + x2 = 44

Factor a perfect square on the left side:
(x + 7)(x + 7) = 44

Calculate the square root of the right side: 6.633249581

Break this problem into two subproblems by setting 
(x + 7) equal to 6.633249581 and -6.633249581.


Subproblem 1
x + 7 = 6.633249581

Simplifying
x + 7 = 6.633249581

Reorder the terms:
7 + x = 6.633249581

Solving
7 + x = 6.633249581

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + x = 6.633249581 + -7

Combine like terms: 7 + -7 = 0
0 + x = 6.633249581 + -7
x = 6.633249581 + -7

Combine like terms: 6.633249581 + -7 = -0.366750419
x = -0.366750419

Simplifying
x = -0.366750419


Subproblem 2
x + 7 = -6.633249581

Simplifying
x + 7 = -6.633249581

Reorder the terms:
7 + x = -6.633249581

Solving
7 + x = -6.633249581

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + x = -6.633249581 + -7

Combine like terms: 7 + -7 = 0
0 + x = -6.633249581 + -7
x = -6.633249581 + -7

Combine like terms: -6.633249581 + -7 = -13.633249581
x = -13.633249581

Simplifying
x = -13.633249581


Solution
The solution to the problem is based on the solutions
from the subproblems.
x = {-0.366750419, -13.633249581}

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